A boy spots a ball that goes up past an open window. The ball, which passes very close to the window, is in view of the boy for 0.25 s while going up, and the top-to-bottom height of the window is 2.0 m. What is the ball’s upward velocity at the bottom of the window? (Take g = 10 m/s2)
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s=ut + 1/2 at^2. 2 = u * 1/4 - 1/2 *10 *1/16. u=9.25 m/s.