Calculate the difference in temperature between the water at the top and bottom of a water fall 200 m high. Specific heat capacity of water is 4200 J/kg k.(consider g=9.8)
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potential energy of water at a height 200 m = m 9.8 200 = m 1960 J using this P.E let the temperature of water rise by \Delta T \Delta Q=mc\Delta T 1960 m = m 4200*\Delta T \Delta T = 1960/4200 =0.4667 K