Water Level

Geometry Level 2

A sphere of radius 6cm is dropped into a cylindrical vessel partly filled with water. The radius of the vessel is 8cm. If the sphere is submerged completely, then the surface of the water rises by

3cm 4.5cm 2cm 4cm

Karan Ahire by Karan Ahire , 21, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

The volume of the sphere is 4 3 π r 3 = 4 3 π ( 6 3 ) = 904.78 \dfrac{4}{3}\pi r^3=\dfrac{4}{3} \pi (6^3)=904.78 .

The volume of the rise of water must also be equal to the volume of the sphere. The volume of a cylinder is area of the base multiplied by the height, so we have

904.78 = π ( 8 2 ) ( h ) 904.78 = \pi (8^2)(h)

h = 4.5 c m \color{#D61F06}\boxed{h=4.5~cm}

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...