Another Young's Double Slit Experiment!

Classical Mechanics Level 4

In a Young's double slit experiment minimum intensity is found to be non zero. If one of the slits is covered by a transparent film which absorbs 10 % 10\% of light energy passing through it, then which one of these is true? (There maybe more than one)

A ) A) Intensity at maxima must decrease

B ) B) Intensity at maxima may decrease

C ) C) Intensity at minima may increase

D ) D) Intensity at minima may decrease

Also see straight lines problem

B , D B,D A , B , C , D A,B,C,D A , B , D A,B,D B , C B,C A , C , D A,C,D N o n e None

Tanishq Varshney by Tanishq Varshney , 23, India

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1 solution

Saurabh Patil
Apr 24, 2015

Resultant intensity at a point is given by ( I r e s u l t a n t ) 2 = ( I 1 ) 2 + ( I 2 ) 2 + 2 ( ( I 1 ) ( I 2 ) ) cos ⁡ θ (I_{resultant})^2 = (I_1)^2 + (I_2)^2 + 2 \sqrt((I_1)(I_2)) \cos\theta where theta is the phase difference angle between the two similar frequency lights incident on screen from the slits.

As the transparent film absorbs 10% light from a slit so the intensity at maxima is surely less than when the film is not there( I_2 decreases )

At the minima the intensity may increase or may decrease. So A, C , D are correct.

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