Wave optics tweaked.

Classical Mechanics Level 3

Two coherent plane light waves of equal amplitude make a small angle ( $\alpha << 1)$ with each other. They fall almost normally on a screen. If $\lambda$ is the wavelength of light waves, the fringe width $\delta x$ of interference patterns of the two sets of waves on the screen is

$sqrt(\alpha)=\sqrt(\alpha)$

\frac{\lambda}{sqrt(\alpha)}

\frac{\lambda}{2\alpha}

\frac{2\lambda}{\alpha}

\frac{\lambda}{4\alpha}

\frac{\lambda}{\alpha}

\frac{4\lambda}{\alpha}

0 solutions

No explanations have been posted yet. Check back later!

Wave optics tweaked.

0 solutions

0 pending reports