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Classical Mechanics Level 4

A circular loop of rope of length L rotates with uniform angular velocity ω \omega about an axis through its center on a horizontal smooth platform. A small displacement is given to radially which makes it produce the pulses. Find the velocity of the pulse (in m/s \text{m/s} ) with respect to the rope.

Details and Assumptions

  • The length of the rope is L = 3 m L = 3 \text{ m} .

  • The angular velocity, ω = 20 π rad/s \omega = 20 \pi \text{ rad/s} .

The problem is not original.


The answer is 30.

Surya Prakash by Surya Prakash , 22, India

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1 solution

Donglin Loo
Nov 27, 2015

Length L = 2 π r L=2\pi r

r = 3 2 π r=\frac{3}{2\pi}

v = r ω v=r\omega

v = 3 2 π × 20 π v=\frac{3}{2\pi}\times 20\pi

v = 30 m / s v=30m/s

14 Helpful 0 Interesting 0 Brilliant 4 Confused

A circular loop of rope of length L rotates with uniform angular velocity Omega about an axis through its center on a horizontal smooth platform.velocity of pulse produced due to slight radial displacement is given by........

MOHD ALEEM - 3 years, 6 months ago

Initially it seemed it would require Mass per unit lenght. But it didnt!! . Well , Better would have been if it asked to find out the velocity of the loop w.r.t a man standing outside the wire.

Md Zuhair - 3 years, 4 months ago

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