Way back in 2009

Algebra Level 5

When ( x 2 + 2 x + 2 ) 2009 + ( x 2 3 x 3 ) 2009 (x^2+2x+2)^{2009} + (x^2-3x-3)^{2009} is expanded, what is the sum of the coefficients of the terms with odd exponents of x x ?


The answer is -1.

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1 solution

Patrick Corn
Apr 29, 2015

Call the polynomial f ( x ) f(x) . Then the sum of the odd coefficients is f ( 1 ) f ( 1 ) 2 \frac{f(1)-f(-1)}2 . Since f ( 1 ) = 0 f(1) = 0 and f ( 1 ) = 2 f(-1) = 2 , the answer is -1 \fbox{-1} .

Eh, is [f(1) - f(-1)]/2 not?

Aditya Dwianto Dwianto - 6 years, 1 month ago

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Edited, thanks for catching.

Patrick Corn - 6 years, 1 month ago

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