A family of ellipsoids is defined by the set of all ellipsoids whose equation is
a 2 x 2 + b 2 y 2 + c 2 z 2 = 1
and passing through the point ( 3 , 4 , 1 2 ) . Find the smallest possible volume of an ellipsoid in this family.
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The volume of the ellipsoid becomes minimum when a=3√3, b=4√3 and c=12√3. The minimum volume is 3 4 π(3√3)(4√3)(12√3)=576√3π
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Applying the AM/GM inequality 3 1 = 3 1 ( a 2 9 + b 2 1 6 + c 2 1 4 4 ) ≥ 3 a 2 b 2 c 2 9 × 1 6 × 1 4 4 = ( a b c 1 4 4 ) 3 2 so the volume of the ellipsoid is V = 3 4 π a b c ≥ 3 4 π × 1 4 4 × 3 3 = 5 7 6 π 3 We can choose a , b , c to obtain equality in the AM/GM inequality, and hence can choose a , b , c to obtain this minimum value of V .