We are moving too fast

An observer is standing on Earth's surface, at the equator. In his frame of reference, what is the speed of the center of the Earth (in m/s \text{m/s} )?

  • Earth's radius at the equator is about 6378 km 6378 \text{ km} .

  • Make sure that you use the correct time period for Earth's rotation.


Image Credit: Wikipedia .


The answer is 464.51.

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1 solution

Pranshu Gaba
Apr 22, 2016

The speed of the center of the earth relative to the observer is equal to the speed of the observer relative to the center of the earth.

If we stood at the center of the earth, we would see that the observer is moving in a circle of radius 6378 km. The circumference of the circle is 2 × π × 6378 40074 2 \times \pi \times 6378 \approx 40074 km. The observer completes one revolution in one sidereal day , which is about 86164 seconds.

Hence the relative speed is about 40074 86164 \dfrac{40074}{86164} km/s, which is approximately 465 m/s. _\square

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