We Need To Go Radically Deeper

Algebra Level 3

x x x x 5 4 3 \large \sqrt{ x \sqrt[3]{x \sqrt[4]{x \sqrt[5]{ x \cdots }} }}

Let e = 2 + 1 1 × 2 + 1 1 × 2 × 3 + 1 1 × 2 × 3 × 4 + e = 2 + \dfrac1{1\times2} + \dfrac1{1\times2\times3}+ \dfrac1{1\times2\times3\times4} + \cdots .

Which of the following is equal to the expression above. (Take x 0 x\geqslant 0 )

x e 2 x^{e-2} x e 1 x^{e-1} x e + 1 x^{e+1} x e + 2 x^{e+2}

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1 solution

Akshat Sharda
Mar 17, 2016

x x x x 5 4 3 = ( x ( x ( x ( x ) 1 5 ) 1 4 ) 1 3 ) 1 2 x 1 2 x 1 2 × 3 x 1 2 × 3 × 4 x 1 2 × 3 × 4 × 5 = x 1 2 + 1 2 × 3 + 1 2 × 3 × 4 + 1 2 × 3 × 4 × 5 + x e 2 \sqrt{ x \sqrt[3]{x \sqrt[4]{x \sqrt[5]{ x \cdots }} }} = \left( x \left( x \left( x \left( x \ldots \right)^\frac{1}{5} \right)^\frac{1}{4} \right)^\frac{1}{3} \right)^\frac{1}{2} \\ x^{\frac{1}{2}}x^{\frac{1}{2×3}} x^{\frac{1}{2×3×4}}x^{\frac{1}{2×3×4×5}}\ldots= x^{\frac{1}{2}+\frac{1}{2×3}+\frac{1}{2×3×4}+\frac{1}{2×3×4×5}+\ldots} \\ \Rightarrow \boxed{x^{e-2}}

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