Wedding cake

Calculus Level 5

So recently I was at my aunt's wedding, and low and behold, I couldn't help my self but think of how I could make a problem out of this. So here it is (this and several other problems I'm about to post are based off of this problem)


A wedding cake of 14 levels is modeled by rotating the function y = x + 1 y=\lfloor x \rfloor +1 from 0 x < 14 0\leq x < 14 around the x-axis. If the answer can be represented as a π a\pi , find a.


The answer is 1015.

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1 solution

Trevor Arashiro
Dec 19, 2014

This is basically a stack of cylinders.

From 0 x < 1 0\leq x < 1 the cylinder will have a radius of 1.

From 1 x < 2 1\leq x < 2 the cylinder has a radius of 2.

This pattern is such that the cylinder from n 1 x < n n-1 \leq x < n will have a radius of n.

The volume of a cylinder is π r 2 h \pi r^2 h and since each cylinder has a height of 1, it can be simplified to π r 2 \pi r^2 .

We are looking at the volume of all the cylinders, so we are looking at

π r = 1 14 r 2 = π ( 1 2 + 2 2 + 3 2 + . . . + 1 4 2 ) \pi \displaystyle \sum_{r=1}^{14} r^2=\pi (1^2+2^2+3^2+...+14^2)

Using this lemma: m = 1 n m 2 = n ( n + 1 ) ( 2 n + 1 ) 6 \displaystyle \sum_{m=1}^n m^2=\dfrac{n(n+1)(2n+1)}{6}

π r = 1 14 r 2 = π 14 ( 15 ) ( 29 ) 6 = 1015 π \pi \displaystyle \sum_{r=1}^{14} r^2=\pi \cdot \dfrac{14(15)(29)}{6}=1015\pi

a π a = 1015 \therefore a\pi\Rightarrow \boxed{a=1015}

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