Weight

Classical Mechanics Level 1

An object's mass is 120 kg \SI{120}{\kilo\gram} . When it is taken away to the moon, it is noticed that the object's mass remains the same but its weight has changed.

What will be the weight (in Newtons) of the object on the moon?


Details and Assumptions:

  • g = 9.8 m / s 2 . g=\SI[per-mode=symbol]{9.8}{\meter\per\second\squared}.
  • The acceleration due to gravity on the moon is 1 6 \frac{1}{6} of that on Earth.


The answer is 196.

Munem Shahriar by Munem Shahriar , 18, Bangladesh

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Munem Shahriar
May 13, 2017

Given that m = 120 k g m = 120 kg

In the moon gravity acceleration is , g = g = 1 6 \dfrac{1}{6} × 9.8 m / s 2 × 9.8 m/s^2

W = m g W = mg

⇒ W = 120 × \Rightarrow W = 120 × 1 6 \dfrac{1}{6} × 9.8 × 9.8 m / s 2 m/s^2

= 196 N = 196N (Answer)

2 Helpful 1 Interesting 0 Brilliant 0 Confused
Tapas Mazumdar
May 8, 2017

The weight of an object is defined as the force exerted on it by the field of gravity of another object (here, the planets moon and earth). This force can be calculated via Newton's second law of motion as :

Weight on the moon = F = m a = m g moon = 120 × 9.8 × 1 6 = 196 N \text{Weight on the moon}= F = ma = m g_{\text{moon}} = 120 \times 9.8 \times \dfrac 16 = \boxed{196 N}

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Alex Boone
Jan 30, 2019

F=mg

m=120kg

g=(9.8m/s)÷6=1.63m/s

F=mg=120kg×1.63m/s=196N

F=196N

0 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...