An object weighs in water and in oil, whose specific gravity is . In two decimal places, what is its weight in air, in Newtons? For the problem, use the standard unit weight of water as .
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Suppose that the object has a volume V cubic meters and weighing W Newtons. Being fully submerged in the liquids specified, the displaced volumes would then be equal to V as well, having buoyant forces 9 8 1 0 V and 9 8 1 0 ( 0 . 8 2 ) V = 8 0 4 4 . 2 0 V Newtons.
The respective buoyant forces and the submerged weights are all directed upward; whereas the weight of the body itself, downward. Hence, by vertical force summations in each of the cases,
Water : 9 8 1 0 V + 2 2 = W
Oil: 8 0 4 4 . 2 0 V + 3 0 = W
Solving the set of equations give V = 0 . 0 0 4 5 3 0 5 m 3 and consequently, W = 66.44 N