Let f(x) = tan x for all x between 0 and 180 degrees and gf(x) = sin 5x. Find the value of a+b+c where g(2) = -(a\sqrt{b})/c where a and c are positive coprime integers and b is not divisible by any perfect square other than 1.
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Let f(x) = tan x = 2. Hence cos x = 1/sec x = 1/\sqrt{1+ tan^2 x} = 1/\sqrt{1+2^2} = 1/\sqrt{5}. Since sin^2 x= 1- cos^2 x, sin x = 2/\sqrt{5}. Now, sin 5x = sin (3x+2x) = sin 3x cos 2x + sin 2x cos 3x = (3sin x- 4sin^3 x)(1-2sin^2 x) + 2 sin x cos x(4cos^3 x - 3cos x) Substituting the two values of sin x and cos x, we get sin 5x = -38/(25\sqrt{5}) = -(38\sqrt{5})/125. Hence a=b+c = 38+5+125 = 168.