Weird Looking Star

Geometry Level 1

The above diagram shows 7 equilateral triangles in a regular heptagon (7 sides). The remaining region, colored purple, in the heptagon is a ​ 7-sided pointy star ​ whose perimeter is 70. Then what is the perimeter of the regular heptagon?

21 35 49 63

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4 solutions

Sam Bealing
Apr 21, 2016

Relevant wiki: Length and Area

Each side of the heptagon contributes two sides to the star. As the triangles are equilateral all these sides are the same length. The perimeter of the heptagon is therefore:

70 2 = 35 \dfrac{70}{2}=35

Hana Wehbi
May 9, 2016

Perimeter of the pointy star is 70, thus 70 14 \frac{70}{14} = 5 5 is the measure of each side of the equilateral triangle. The perimeter of the heptagon is 5 7 = 35 5*7=35 .

Yehuda Davis
May 1, 2016

Each point has 2 equal sides and there are 7 equal points so the star's outer perimeter consists of 14 equal sides so we can divide 70 by 14 we get 5 and since the triangles have equal sides the heptagon's outer perimeter consists of 7 sides each 5 long so we multiply 7 by 5 and get 35

Ashish Menon
May 28, 2016

The pointy star is made up of 14 sides of an equilateral triangle. So, the length of the side of an equilateral triangle is 70 14 = 5 \dfrac{70}{14} = 5 . Since all sodes of an equilateral triangle are equal. The length of one side of the regular heptagon is 5 5 . Since the heptagon consists of 7 sides, the perimeter of the regular heptagon is 7 × 5 = 35 7 × 5 = \color{#69047E}{\boxed{35}} .

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