Weird Ratio

Geometry Level 3

In A B C \triangle{ABC} , Let D D and E E be the trisection points of B C BC with D D between B B and E E . Let F F be the midpoint of A C AC , and let G G be the midpoint of A B AB . Let H H be the intersection of E G EG and D F DF . If the ratio E H : H G EH:HG equals a : b a:b where a , b a,b are relatively prime positive integers. Find a + b a+b .


The answer is 5.

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1 solution

Roshan Ouseph
Aug 28, 2014

Join the points G and F. So, GF || BC and GF = BC/2.

Triangles EHD and GHF are similar. So EH/GH = ED/GF = (BC/3)/(BC/2) = 2/3 = a/b

Therefore, a + b = 5.

where u get that BC/3 from plz explain

will jain - 6 years, 6 months ago

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because ED = BC/3 ( It's given)

Lalit Jena - 5 years, 6 months ago

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