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Find the last digit of the number,

1 ! + 2 ! + 3 ! + + 2016 ! . \large {1! + 2! + 3!+ \cdots+2016!}.


The answer is 3.

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1 solution

Anuj Shikarkhane
Jan 17, 2016

1 ! = 1 1! = 1 .

2 ! = 2 2! = 2 .

3 ! = 6 3! = 6 .

4 ! = 24 4! = 24 .

5 ! = 120 5!=120 .

6 ! = 720 6! = 720 .

5 ! 5! is 120 120 . So, the remaining factorials will all have their last digit as 0 0 .

1 + 2 + 6 + 24 = 33 1 + 2 + 6 + 24 = 33 .

So the last digit of the expression is 3.

(Upvote if you are satisfied)

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