Well of death

Classical Mechanics Level pending

A particle of mass 1 1 kg. moves along the internal smooth surface of a vertical cylinder of radius 1 1 m. Initially the velocity of the particle is 1 1 m.s 1 ^{-1} making an angle of 45 ° 45\degree with horizontal. With what force in Newton does the particle act on the cylinder?


The answer is 0.5.

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1 solution

The horizontal component of velocity of the particle remains constant throughout the course of motion since there is no acceleration in this direction. This component is v 0 cos α = 1 2 v_0\cos α=\dfrac{1}{\sqrt 2} . Here v 0 = 1 v_0=1 ms 1 ^{-1} is the initial velocity of the particle and α = 45 ° α=45\degree is the angle of projection. Hence the force exerted by the particle on the wall of the cylinder is m v 0 2 R cos 2 α = 0.5 \dfrac{mv_0^2}{R}\cos^2 α=\boxed {0.5} N ; m = 1 m=1 kg. and R = 1 R=1 m. are the mass of the particle and the radius of the cylinder respectively.

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