A particle of mass kg. moves along the internal smooth surface of a vertical cylinder of radius m. Initially the velocity of the particle is m.s making an angle of with horizontal. With what force in Newton does the particle act on the cylinder?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
The horizontal component of velocity of the particle remains constant throughout the course of motion since there is no acceleration in this direction. This component is v 0 cos α = 2 1 . Here v 0 = 1 ms − 1 is the initial velocity of the particle and α = 4 5 ° is the angle of projection. Hence the force exerted by the particle on the wall of the cylinder is R m v 0 2 cos 2 α = 0 . 5 N ; m = 1 kg. and R = 1 m. are the mass of the particle and the radius of the cylinder respectively.