a b = 1 , b c = 2 , c a = 3 If a , b , c are rational,then a + b + c = ?
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You may want to clarify that the answer should be rounded to four decimal places.
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...did you say four decimal places?
@Michael Mendrin Same way sir!! Umm Sir, there is a typo in the last line.........it should be 22/3 instead.......!!
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..force of habit... you know, 7 2 2 ≈ π
admirable sir! though it's latest version of detecting the solar prominence...
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If a b = 1 , then a could be either 1 or − 1 . We check out the possibilities, we can't be sure if any solution in reals exists for a = − 1 .
If a = 1 , then c = 3 , so that b = 2 3 1 which is not rational.
But if a = − 1 , then c = 3 1 , so that b = 2 3 = 8 , which is rational, and ( − 1 ) 8 = 1 does check out.
In this case, a + b + c = 2 2 / 3 = 7 . 3 3 3 3 . . .