What a Coincidence!
A group of seven young men named Arun , Binoy , Chunder , Dev , Edward, Fakruddin and Govind were recently engaged in a game. They had agreed that whenever a player won a game he should double the money of each of the other players, in other words he has to give the players just as much money as they had already in their pockets. In all they played seven games and, strangely, each won a game in turn in order in which their names are given. But what was even more strange was that when they had finished the game each of the seven young men had exactly the same amount, Rs. 32 in his pocket. Can you find out how much money did arun have with him before they began the game?(in Rs)
The answer is 112.25.
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1 solution
A simple general solution to this problem would be as follows:
let's assume there are n number of players. Then the amount held by every player at the end will be m(2^n), and the last winner must have held at the start m(n+1), the next m(2n + 1), the next m(4n+1) and so on to the first player, who must have held m(2^(n-1) n+1). Therefore in this case , n = 7 And the amount held by every player at the end was 2^7 quarter of a rupee pieces. Therefore , m = 1 Arun started with 449 quarter of a rupee pieces or Rs 112.25