What A Lucky Coincidence

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The area, in the Cartesian plane, between the two parabolas α \alpha ( y + a b = x 2 y + \frac{a}{b} = x^2 ) and β \beta ( y + x 2 = a b y + x^2 = \frac{a}{b} ) is a b \frac{a}{b} , for positive integer coprime values of a a and b b .

Evaluate a + b a+b .


The answer is 73.

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1 solution

Tom Engelsman
Feb 7, 2021

Both of these parabolas are symmetric with respect to the coordinate axes. At y = 0 y=0 , we have x = ± a b x = \pm \sqrt{\frac{a}{b}} . The area between these curves is thus partitioned into four equal quadrants and can be computed as:

A = 4 0 a / b x 2 + a b d x 4 [ x 3 3 + a b x ] 0 a / b = 8 3 ( a b ) 3 / 2 = a b a b = 9 64 a + b = 73 . A = 4\int_{0}^{\sqrt{a/b}} -x^2 + \frac{a}{b} dx \Rightarrow 4[-\frac{x^3}{3} + \frac{a}{b} x]|_{0}^{\sqrt{a/b}} = \frac{8}{3} (\frac{a}{b})^{3/2} = \frac{a}{b} \Rightarrow \frac{a}{b} = \frac{9}{64} \Rightarrow a+b = \boxed{73}.

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