What a quadrilateral!

Geometry Level 4

Compare A C + B D AC + BD and A B + B C + C D + D A 2 \dfrac{AB + BC + CD + DA}{2}

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It's easy, believe me!

A C + B D > A B + B C + C D + D A 2 AC + BD > \frac{AB + BC + CD + DA}{2} A C + B D < A B + B C + C D + D A 2 AC + BD < \frac{AB + BC + CD + DA}{2} It depends on what kind of quadrilateral you were talking about. A C + B D = A B + B C + C D + D A 2 AC + BD = \frac{AB + BC + CD + DA}{2}

Thành Đạt Lê by Thành Đạt Lê , 17, Singapore

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1 solution

Saksham Jain
Nov 11, 2017

let O be the intersection of diagnols then use sum of 2sides is>3rd in a triangle in 4 triangles add up simplify you have arrived at answer

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