Two volatile liquids and are taken in two separate container and . 10 moles Liquid is poured in container and 5 moles of liquid is poured in container . Now in container , 5 moles of non-volatile solute (molecular formula MX2) is mixed whereas in container , 3 moles of another non -volatile solute Y(molecular formula M2X3)h is mixed.
Now the two solutions formed in and are mixed together mixed in third container. Now the total vapour pressure of mixture of is noted and reported. Find the reported Vapour pressure.
Given:-
Vapour pressure of A and B in pure state is 180 mm Hg and 270 mm Hg respectively.
solutions are ideal
non-volatile solutes ionize completely in A and B
All components of solutions are non-reacting.
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Other way of understanding could be
Let us first mix A and B
Then pressure measured is
P = P A X A + P B X B = 2 1 0 m m o f H g
Now you added solute
Effective moles of solute added = 5 × 3 for X and 3 × 5 for Y = 30 moles
Now , using lowering of vapour pressure formula
P ○ P ○ − P s = m o l e f r a c t i o n o f s o l u t e
P s = 7 0 m m o f H g