What an ant can do?
An ant is at a corner of a cubical room of a side . The ant can move with a constant speed . What is the minimum time taken to reach the farthest corner of the cube?
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it is an easy question but a tricky one all are thinking to be reach farthest corner through √3a but how an ant can fly in air
the only way is to think like book (cubical)
first think like 4th book in given image now to reach farthest corner as ant cannot fly open book as in figure 2 . Now length became 2a and breath became a ( after opening the book ) applying Pythagoras theorem we obtain final distance to be √5a. Also speed = distance/time hence time = distance/speed. So minimum time to reach farthest corner by an ant is √5a/u.