What are the divisors of 3?

If 3 X \frac 3X is an integer, then which of the following must be an integer as well?

4 X \frac4X 5 X \frac5X 6 X \frac6X

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

4 solutions

Marta Reece
Jul 30, 2017

6 X = 2 × 3 X \frac6X=2\times\frac3X

Multiplying an integer by 2 2 produces an integer.

The other numerators are not multiples of 3 3 and so those numbers need not be integers.

Mohammad Khaza
Feb 9, 2018

3 x × 2 = 6 x \frac{3}{x} \times 2=\frac{6}{x}

so, 6 x \frac{6}{x} must be an integer.

Noel Lo
Jul 31, 2018

6 X = 2 × 3 X = 2 ( 3 X ) \dfrac{6}{X}=\dfrac{2\times3}{X}=2\left(\dfrac{3}{X}\right)

In this problem, x x must be a multiple of 3 3 .

Wrong. 9 is a multiple of 3, but 3/9 is not an integer.

What you're looking for is the word "factor / divisor," not "multiple."

Pi Han Goh - 3 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...