If X 3 is an integer, then which of the following must be an integer as well?
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x 3 × 2 = x 6
so, x 6 must be an integer.
In this problem, x must be a multiple of 3 .
Wrong. 9 is a multiple of 3, but 3/9 is not an integer.
What you're looking for is the word "factor / divisor," not "multiple."
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X 6 = 2 × X 3
Multiplying an integer by 2 produces an integer.
The other numerators are not multiples of 3 and so those numbers need not be integers.