What is this fraction?

Suppose that the proper fraction is $\dfrac{x}{y}$ $; x < y$

x + y = 14............................................................(1)

y - x = 8 ..............................................................(2)

(+)

$⇒$ $2y = 22$

$⇒ y =$ $\dfrac{22}{2}$

$y = 11$

Place value of $y$ to get $x$

$x + 11 = 14$

$⇒ x = 14 - 11$

$x = 3$

Therefore, $\dfrac{3}{11}$ is the proper fraction.

let the fraction be $\dfrac{y}{x}$ , then

$x+y=14$ (1)

$x-y=8$ (2)

adding the two equations gives

$2x=22$

$x=11$

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$y=x-8=11-8=3$

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The fraction is $\boxed{\dfrac{3}{11}}$ .