What could this limit be?

Calculus Level 4

lim n ( n ! n n ) 1 n = ? \Large \lim_{n \to \infty} \left(\frac {n!}{n^n} \right)^\frac 1n = \ ?

0 0 π 2 \frac{\pi}{2} 1 1 π 4 \frac{\pi}{4} Limit does not exist e e 1 / e 1/e π \pi

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3 solutions

Rishav Koirala
Jul 4, 2016

Let If one replaces r / n r/n by x x and 1 / n 1/n by d x dx , the equation now becomes

I'm going to use Stirling formula lim n ( n ! n n ) 1 n = lim n ( 2 π n ( 1 n ) ( n e ) n ) = 1 e \displaystyle \lim_{n\to \infty} \left(\frac{n!}{n^n}\right)^{\frac{1}{n}} = \lim_{n\to \infty} \left(\frac{\sqrt{2\pi n}^{(\frac{1}{n})}\left(\frac{n}{e}\right)}{n}\right) = \frac{1}{e} due to lim n 2 π n 2 n = 1 \displaystyle \lim_{n\to\infty} \sqrt[2n]{2\pi n} = 1

Did the aame

Aditya Kumar - 4 years, 11 months ago

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Well done,haha! I almost always use Stirling's formula in limits when the factorial number is inside of it. Almost always, but not always..

Guillermo Templado - 4 years, 11 months ago

Wow ,thanks for sharing a new technique ., i did not know this technique .

Ujjwal Mani Tripathi - 4 years, 11 months ago

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thank you very much, this new formula formula for you is an old known formula for me, haha... it's not you,it's me, I'm getting older...

Guillermo Templado - 4 years, 11 months ago

Also did it the same way!

rishabh singhal - 4 years, 10 months ago
Shubham Dhull
Oct 19, 2017

using e p s i l o n epsilon - d e l t a delta definition :p

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