If ( a − b ) 2 = ( a + b ) 2 , then what is the value of a b ?
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\[\begin{align} (a-b)^2 &= (a+b)^2 \\ \cancel{a^2 + b^2} - 2ab &= \cancel{a^2 + b^2} + 2ab \\ -2ab &= 2ab \\ 4ab &= 0 &\blue{\text{Since } 4 \ne 0 \text{ divide the equation by } 4} \\ ab &= \boxed{0}
\end{align}\]
Starting from the identity: ( a + b ) 2 − ( a − b ) 2 = 4 a b As ( a + b ) 2 = ( a − b ) 2 ⇒ ( a + b ) 2 − ( a − b ) 2 = 0 ⇒ 4 a b = 0 ⇒ a b = 0
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(a-b)²=(a+b)²
a²-2ab+b²=a²+2ab+b²
-2ab=2ab
4ab=0
ab=0
either a is 0 or b is 0
Thus, ab=0.