What Does A Charged Sphere Do In An Electric Field?

An electric field is uniform throughout a certain region of space. Its magnitude is 10 V/m 10~\mbox{V/m} . A conducting sphere of radius R = 1 cm R=1~\mbox{cm} and charge Q = 1 μ C Q=1~\mu\mbox{C} is then placed in this region. Determine the magnitude of the electric field at the center of the sphere.

  • k = 1 4 π ϵ 0 = 9 × 1 0 9 N m 2 / C 2 k=\frac{1}{4\pi \epsilon_{0}}=9\times 10^{9}~\mbox{N m}^{2}/\mbox{C}^{2}


The answer is 0.00.

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5 solutions

Arijit Banerjee
Mar 5, 2014

Charge resides only on the surface of a conducting sphere. So if we assume a Gaussian surface inside the sphere around the centre then charge enclosed is 0. So, from Gauss's Law, we get intensity 0.

you are right agree with your comment

moideen madathil - 7 years, 2 months ago

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Thanks!

Arijit Banerjee - 7 years, 2 months ago
Argha Pp
Mar 11, 2014

Friends, forget about gauss' law. electric field inside a charged conductor is always 0 even if it is placed inside any electric field . it is because a conductor has many free electrons and when that conductor is placed in E field those electrons align themselves in such a way that E field inside conductor remains 0.

why gauss's law is applicable only on closed surfaces??

Vineet Kumar - 7 years, 1 month ago
Nawaz Khan
Apr 27, 2014

it is conceptual one as the values are given just to confuse someone as according to gauss,s law application that electric field intensity inside a charged hollow sphere is always zero.

Shoaib Saifi
Mar 12, 2014

there is no electric field inside a conducting body.

Soorya Narayan
Mar 5, 2014

From Gauss' law, all charge is present on the sphere surface and hence there is no electric field at the center.

why gauss's law is applicable only on closed surfaces??

Vineet Kumar - 7 years, 1 month ago

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