Two objects of mass 5 kg and 2 0 kg are attached to a spring with a spring constant k (in Newtons per meter) and length l meters.
The angular frequency of the oscillation of this system when the spring is compressed by a force F Newtons and then released is given by a k b l c F d , where a , b , c , and d are constants.
Find a + b + c + d .
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That's cool. So just take the easily derived result from the 1-mass-1-spring case ( m k ). Then calculate the equivalent single mass as the product over the sum of the two masses (yielding 4 kg). Then you get 2 1 k 2 1 l 0 F 0 . So a + b + c + d = 2 1 + 2 1 + 0 + 0 = 1 .
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Walter Lewin does a good job explaining the idea of an "equivalent spring constant" here: https://www.youtube.com/watch?v=mE6lQCdzb1M Alternatively, you could also think of an equivalent mass, usually called the reduced mass, where like the equivalent spring constant, you take the harmonic sum of the masses.