What Happens When Polarized Light Falls On A Polarizer?
A beam of linearly polarized light falls on a polarizer which rotates about the axis of the beam with angular speed . Find the energy in mJ of the light passing through the polarizer per one revolution if the flux of the incident light is .
The answer is 3.14159.
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to make one revolution, polarizer takes pi/5 sec. To find the total energy passing through the polarizer, we need to integrate P 0 (cos(10t))^2 (the fraction of power passing through the polarizer at time t) over t = 0 to t = pi/5 which gives the required answer P 0*pi/10 = 3.14mJ