What is it's measure?

Geometry Level pending

In a rectangle A B C D ABCD there are two semicircles with radius 173 cm 173 \text{ cm} , they just touch each other at a point G G and both the semicircles also touches the point A and point C respectively. If B C BC measure 104 cm 104 \text{ cm} , then what is the measure of A B AB in centimetres?

Note: It is not necessary that the semicircles fully lie inside the rectangle, only there center lies on the side of the rectangle.


The answer is 676.

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2 solutions

A B = 173 + ( 2 × 173 ) 2 10 4 2 + 173 = 676 |\overline {AB}|=173+\sqrt {(2\times 173)^2-104^2}+173=\boxed {676} cm.

Good, writing the big in a single line!

Zakir Husain - 1 year ago
Zakir Husain
May 24, 2020

Let the centers of the two semi-circles be O O and O O' Join O O and O O'

Draw a line from O O to A B AB perpendicular to A B AB intersecting A B AB at J J

In triangle O O J OO'J

O J 2 + O J 2 = O O 2 OJ^2+O'J^2=OO'^2

10 4 2 + O J 2 = 34 6 2 104^2+O'J^2=346^2

O J = ( 346 104 ) ( 346 + 104 ) = 108900 = 330 O'J=\sqrt{(346-104)(346+104)}=\sqrt{108900}=330

A B = O A + O J + O C = 173 + 330 + 173 = 676 AB=O'A+O'J+OC=173+330+173=\boxed{676}

The diagram actually helped me as I was thinking why you put O O O O^{'} . I would suggest you to remove this line for making it harder. Thanks!

Vinayak Srivastava - 1 year ago

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