A natural number has a remainder of 3 when divided by 7 and also has a remainder of 4 when divided by 5. What is the smallest possible value of ?
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Since we have
{ N ≡ 3 i m o d i 7 N ≡ 4 i m o d i 5
By the Chinese Remainder Theorem, there is only one solution modulo 3 5 , namely
N ≡ 2 4 i m o d i 3 5
And since N is natural, the minimal N is 2 4