An algebra problem by Sarthak Chittawar

$\begin{aligned} 3050^2 - 4950^2 & = (3050+4950)(3050-4950) \\ & = 8000 (-1900) \\ & = \boxed {-15 \ 200 \ 000} \end{aligned}$

Lazy method:

3050 and 4950 both end in a 0, so the answer must end in 0.

4950>3050, so the answer must be negative.

The only option that satisfies both criteria is -15200000.