Consider all rectangles with integer side lengths and an area of 7 2 m 2 . What is the minimum possible perimeter?
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F i n d i n g t h e m i n i m u m p e r i m e t e r m e a n s t h a t t h e d i f f e r e n c e b e t w e e n t h e s i d e l e n g t h s s h o u l d b e t h e s m a l l e s t .
For 7 2 the minimum difference is 1 by multiplying 8 into 9 which can be found out by trial and error. Therefore the minimum perimeter is 34 m...... 2 x ( 8 + 9 )
Min means all sides
Use square roots to find the sides
Multiply by four
@Thomas Lowry Wouldn't the answer be 4 7 2 ? Are we assuming that the sides must be an integer?
If you use derivatives to find the answer, you get a function of the perimeter: P(a) = 2 (a + 72/a), which has it's minimum at a = 6sqrt(2), yet the answer needs to be an integer ( my answer would be 24sqrt(2) ). What am I missing?
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Thanks. I have edited the problem for clarity.
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here it is,
72 =8 x 9
o, the perimeter is ={(8 + 9) x 2}