What is the position in function of time?

Level pending

A particle of mass m is suspended from the ceiling by a spring with constant K and relaxed length initial lo, whose mass is negligible. The particle is released at rest with the spring relaxed. Taking the Oz axis directed vertically downward, with the origin on the roof, calculate the z position of the particle as a function of time.

z(t)=Lo+(mg/k)*(1-sen(sqrt(k/m)t z(t)=Lo+(mg/k)*(1-tg(sqrt(k/m)t z(t)=Lo+(mg/k)*(1+sen(sqrt(k/m)t z(t)=Lo+(mg/k)*(1-cos(sqrt(k/m)t

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

0 solutions

No explanations have been posted yet. Check back later!

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...