In triangles and , and are equal. Sides and are of equal length. Sides and are also of equal length. Length of side is twice that of side . The ratio of lengths and must lie in the range . What is the magnitude of ?
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So we can put those two triangles into one (as shown on the picture). And now we can set up equation by the rule of cosines for a:
a 2 = a 2 + b 2 / 4 − 2 ∗ a ∗ ( b / 2 ) c o s ( γ )
b = 4 a c o s ( γ )
and now for c:
c 2 = a 2 + b 2 / 4 − 2 ∗ a ∗ ( b / 2 ) c o s ( 1 8 0 ° − γ ) And here we can plug b=4acos(γ) and if we simplify that we will get this:
c 2 = a 2 ( 1 + 8 c o s 2 ( γ ) )
Now the ration is:
a / c = s q r t ( 1 / ( 1 + 8 c o s 2 ( γ ) ) ) And here we can easly see that minimum is when cos^2(γ)=1 and maximum when cos^2(γ)=0.
[p,q]=[1/3;1] So the answer is 2.