What is the real value of x?
Algebra
Level
2
If x is positive, What is the real value of x?
4(X^4) = 333506 + 2(X^2)
The answer is 17.
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1 solution
4(X^4) = 333506 + 2(X^2)
create new variable --> y=x^2
4y^2 = 333506 + 2y
4(y^2) - 2y -333506 = 0
Use quadratic formula
and you get 2 values,
y1= 289 and y2= -577/2
y= x^2
x is real number
x = \sqrt{y}
y2 is negative, => square root of y2 is a number imaginary but x is real!!!
x = \sqrt{y1} = \sqrt{289}
x=17