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1 solution
2tan-1 (x) = tan-1 (2x/(1-x^2 ))
keeping this in mind: 2A= 2*tan-1 (b/2h) 2A = tan-1 (4bh/(4h^2-b^2 ))
Now compare 2A and B. The equation would reduce to b^2>0 in case of B<2A, would come to b^2=0 in case of B=2A.