What is the remainder when (67!) is divided by 71 ?

Find the remainder when (67!) divided by 71.


The answer is 12.

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1 solution

Vijay Simha
Mar 19, 2018

By Wilson’s theorem

70! ≡ −1 mod 71

We know that 71 is a prime number.

Since 70! = 70×69×68×67! , we have

70×69×68×67! ≡ −1 mod 71

or

(−1)×(−2)×(−3)×67! ≡−1 mod 71

or

6×67! ≡ 1 mod 71.

Multiplying both sides by 12

72×67! ≡ 12 mod 71

This means that

1×67! ≡ 12 mod 71.

or

67! ≡ 12 mod 71.

The answer is 12.

it's a good solution

bohan nie - 3 years, 2 months ago

I went for a lengthy calculation, 67 ! 469 2 1 m o d 71 67!\equiv4692^{-1}\mod 71 , but your solution is good.

Shreyansh Mukhopadhyay - 3 years, 2 months ago

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