What is the sum of the coefficients of this expression?

Algebra Level pending

Find the sum of the coefficients of the following expression: ( a 2 b + 67 c 100 d + 200 e ) 2 . (a-2b+67c-100d+200e)^2.


The answer is 27556.

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2 solutions

Whenever you have a problem of this type, just set all the variables equal to 1 1 (because only then all the coefficients of each term will remain) and evaluate. So in this case:

\begin{aligned}(a-2b+67c-100d+200e)^2\xrightarrow[\text{variables = 1}]{\text{}}&(1-2+67-100+200)^2\\ &=(166)^2\\ \text{\$\sum\$ of the coefficients}&=27556. \end{aligned}

Pratik Ranjan
May 1, 2014

we know (1+x)^n has an expansion of nc0+nc1x+nc2x^2+nc3x^3........... putting x=1 we see rhs becam nco+nc1+nc2+nc3...... which is equal to sum of coeeficients and which is equl to (1+1)^n= 2^n applying same terminology for given question ... putting value of a,b,c,d,e =1 we get 166^2=27556

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