∑ n = 0 1 0 0 ∣ ∣ ∣ ∣ ∣ ∣ ⎣ ⎡ ( i + j i ) , 0 ≤ i ≤ n , monotonically increasing 0 ≤ j ≤ n , monotonically increasing ⎦ ⎤ ∣ ∣ ∣ ∣ ∣ ∣
Each or the elements of the square matrix is a binomial number. The matrix is enclosed in square brackets above. The vertical bars indicate the computation of the determinant of the square matrix so constructed. For a 3 × 3 matrix, that matrix would be 1 1 1 1 2 3 1 3 6 .
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Do you have proof that they are all equal to 1?
Exhaustive, I evaluated them all.
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If you row reduce the matrix on the way to computing the determinant, then you will get an identity matrix. The determinant of an identity matrix is always 1.
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Each of the determinants has a value of 1 . There are 101 determinants. The sum is 101.