A googol is equal to .
What is the sum of the smallest 2 prime numbers that divides "googol plus one"?
Hint: The largest prime factor of the number 123456787654321 is the second prime number which divides Googol + 1
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The polynomial X^m+1 is divisible by the polynomial X+1, when m is odd
This means that whatever positive integer you substitute for X in X^m+1 when m is odd, the result will be divisible by X+1. Hence, X^m+1 cannot be prime (unless m=1 or you've substituted 1 for X, in which case the divisor we found, X+1, is the same as the number X^m+1).
This explains why 2^5+1=33 is divisible by 2+1=3
This is why 10^3+1=1001 is divisible by 10+1=11
This is why 77^77+1 is divisible by 77+1=78.
We don't even need to calculate that big number to the left, we already know it's divisible by 78.
Now, all we need to do is take m=25 (which is odd) and X=10^4 to find that
(10^4)^25 +1 is divisible by 10^4+1
So Googol+1 is divisible by 10,001. It is not a prime number.
10001 is itself equal to 73 x 137, 73 is the smallest prime number which divides Googol and 137 is the next prime number which divides it.