An algebra problem by A Former Brilliant Member

solution 1

$3x+4=4x-6$

Subtract $3x$ from both sides to isolate $x$ on the right side.

$3x-3x+4=4x-3x-6$

$4=x-6$

Add six to both sides.

$4+6=x-6+6$

$10=x$

or it can be written as

$x=10$

solution 2

$3x+4=4x-6$

Subtract $4$ from both sides.

$3x+4-4=4x-6-4$

$3x=4x-10$

Subtract $4x$ from both sides.

$3x-4x=4x-4x-10$

$-x=-10$

Divide both sides by $-1$ .

$x=10$

There are other solutions here. Just note that the thing that you do on the left side of the equation, you must also do it on the right side of the equation until the variable is isolated.