What is the value of x in terms of a,b and c?

Algebra Level 3

If x + a b + c + x + b c + a + x + c a + b + 3 = 0 \dfrac{x+a}{b+c} +\dfrac{x+b}{c+a}+\dfrac{x+c}{a+b} +3=0 and a , b , c a,b,c are greater than 0 then find x.

− ( a + b + c ) -(a+b+c) a + b + c \sqrt{a+b+c} a + b + c a+b+c ( a + b + c ) 2 (a+b+c)^2

Vinayak Bansal by Vinayak Bansal , 17, India

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1 solution

Vinayak Bansal
May 25, 2018

Put x + a b + c = x + b c + a = x + c a + b = − 1 \dfrac{x+a}{b+c} =\dfrac{x+b}{c+a}=\dfrac{x+c}{a+b} =-1

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