John was driving his car to the city A to visit his family. He was in constant velocity and see 3 transit signs informing the distance left to arrive in city A.
He saw one sign informing:
"City A left"
After 45 minutes he saw other sign:
"City A left"
After 45 minutes he saw more other sign:
"City A left"
What was the speed that John was driving?
Note: a0b , ba and ab are 3 and 2 digit numbers. The a0b have the 0 on middle.
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Time taken in both intervals(from a0b to ba and from ba to ab) are same=45min If speed is constant, then distance travelled in both intervals is same. From there we get 6a=b. Now possible values of a0b could be between 101-109 as half of it is 2 digit number.. So 106 is only number satisfying two conditions. Hence a=1 and b=6 Hence got distances now find speed.