What is the volume of this shape?

Calculus Level 3

This problem’s question: {\color{#D61F06}\text{This problem's question:}} What is the volume of this shape?

This problem, since only a numeric answer is needed, is most easily solved by a numeric integration.

The formula for the shape: 0.0641500299099584 x 2 + y 2 1.25 + z 2.5 1 0.0641500299099584 \left| x^2+y^2\right| ^{1.25}+\left| z\right| ^{2.5}\leq 1 .

The accuracy of the first numeric value is far in excess of what is needed. Use as much as you think you need.


The answer is 42.4131047962912.

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2 solutions

D G
Jun 18, 2019

Let a = 0.0641500299099584 a = 0.0641500299099584 . We can rewrite the equation as

x 2 + y 2 ( 1 z 5 / 2 a ) 4 / 5 |x^2 + y^2| \leq \left(\frac{1 - |z|^{5/2}}{a}\right)^{4/5}

This is just a circle in the x-y plane. Our volume is then

2 0 1 π ( 1 z 5 2 ) 4 5 a 4 5 d z = 4 2 2 5 π Γ ( 7 10 ) Γ ( 4 5 ) 3 a 4 5 2 \int_{0}^{1} \frac{\pi \left(1 - z^{\frac{5}{2}}\right)^{\frac{4}{5}}}{a^{\frac{4}{5}}}\, dz = \frac{4 \cdot 2^{\frac{2}{5}} \sqrt{\pi} \Gamma\left(\frac{7}{10}\right) \Gamma\left(\frac{4}{5}\right)}{3 a^{\frac{4}{5}}}

Substitute the value of a a to get the final result.

Thank you.

The original form of a a is 1 9 3 \frac{1}{9\sqrt{3}} .

With the original form of a a and using the methodology you apparently used, I came to dissimilar looking solution, but mathematically the same: 18 2 + 2 5 π 2 Γ ( 7 5 ) Γ ( 4 5 ) Γ ( 11 5 ) -\frac{18 \sqrt{2+\frac{2}{\sqrt{5}}} \pi ^2 \Gamma \left(\frac{7}{5}\right)}{\Gamma \left(-\frac{4}{5}\right) \Gamma \left(\frac{11}{5}\right)} .

I have registered a problem report (4272791) with Wolfram. Numerically, the answer to the problem is too dissimilar to the correct answer. The numeric answer to the symbolic form is 42.4131047962912.

I now see that Wolfram/Alpha returns your form of the definite integral (after moving outside the integration the constant terms): 0 1 ( 1 z 5 / 2 ) 4 / 5 d z = 2 2 2 / 5 Γ ( 7 10 ) Γ ( 4 5 ) 3 π \int_0^1 \left(1-z^{5/2}\right)^{4/5} \, dz=\frac{2\ 2^{2/5} \Gamma \left(\frac{7}{10}\right) \Gamma \left(\frac{4}{5}\right)}{3 \sqrt{\pi }} .

The indefinite integral is: 1 3 z ( 2 2 F 1 ( 1 5 , 2 5 ; 7 5 ; z 5 / 2 ) + ( 1 z 5 / 2 ) 4 / 5 ) \frac{1}{3} z \left(2 \, _2F_1\left(\frac{1}{5},\frac{2}{5};\frac{7}{5};z^{5/2}\right)+\left(1-z^{5/2}\right)^{4/5}\right) .

A Former Brilliant Member - 1 year, 11 months ago

Volume [ ImplicitRegion [ Evaluate [ z h p + x 2 + y 2 r p /. { p 2.5 , r 3. , h 1. } ] 1 , ( x 3 3 y 3 3 z 3 3 ) ] ] 42.0705845239179 \text{Volume}\left[\text{ImplicitRegion}\left[\text{Evaluate}\left[\left| \frac{z}{h}\right| ^p+\left| \frac{\sqrt{x^2+y^2}}{r}\right| ^p\text{/.}\, \{p\to 2.5,r\to 3.,h\to 1.\}\right]\leq 1, \\ \left( \begin{array}{ccc} x & -3 & 3 \\ y & -3 & 3 \\ z & -3 & 3 \\ \end{array} \right)\right]\right] \Rightarrow 42.0705845239179

Please, see my comments on D G's solution.

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