What kind of function is this?

Algebra Level 3

A function f ( x ) f(x) has following traits:

f ( 1 ) = 78 , f ( 2 ) = 7878 , f ( 3 ) = 787878 , f ( 4 ) = 78787878 , \begin{aligned} f(1) &=78, \\ f(2)&=7878,\\ f(3)&=787878,\\ f(4)&=78787878,\end{aligned}

and so on. Given that the function can be written as only one of the following expressions:

y = a x 2 + b x + c y = a b x + c y = a x b + c y = a log b ( c x ) \begin{aligned} y&=ax^2+bx+c\\ y&=ab^x+c\\ y&=ax^b+c\\ y&=a\log_b(cx) \end{aligned}

where a a , b b , and c c are constants. Which one is the correct expression?

y = a log b c x y=a\log_bcx y = a x b + c y=ax^b+c y = a x 2 + b x + c y=ax^2+bx+c y = a b x + c y=ab^x+c

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1 solution

Chew-Seong Cheong
Mar 20, 2018

Let f ( 0 ) = 0 f(0) = 0 , we note that for positive integers k k :

f ( k ) = 78 ( 10 0 k 1 ) + f ( k 1 ) f ( k ) f ( k 1 ) = 78 ( 10 0 k 1 ) k = 1 n ( f ( k ) f ( k 1 ) ) = k = 1 n 78 ( 10 0 k 1 ) f ( n ) = 78 ( 10 0 n 1 ) 100 1 Replace n with x f ( x ) = 26 33 10 0 x 26 33 = a b x + c \begin{aligned} f(k) & = 78(100^{k-1})+f(k-1) \\ f(k) - f(k-1) & = 78(100^{k-1}) \\ \sum_{k=1}^n \left(f(k) - f(k-1) \right) & = \sum_{k=1}^n 78(100^{k-1}) \\ f(n) & = \frac {78(100^n - 1)}{100-1} & \small \color{#3D99F6} \text{Replace }n \text{ with }x \\ \implies f(x) & = \frac {26}{33}\cdot 100^x - \frac {26}{33} \\ & = \boxed{ab^x+c} \end{aligned}

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