What kind of number is this?

Find the least positive integer whose last digit is 7 and which becomes 5 times larger when this last digit is carried to front of the number.


The answer is 142857.

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1 solution

Yatin Khanna
Jul 12, 2016

Okay, so this is how I got it.
Since, the last digit is 7 and on shifting it to the starting the number becomes 5 times the original, hence the second last digit must be 5. Now, since the last 2 digits are 57 hence the last 2 digitsof the product will be 85 and therefore, the third last digit is 8.
Continue, using the same logic to arrive at this number i.e. 142857

Also, note that all the results for the following summation where 'n' is any non-negative integer, have the required property.
k = 0 n \displaystyle \sum_{k=0}^n 142857 × 1 0 6 k 142857 × 10^{6k}

I would love to hear from someone as to why this is the same as the repeating digits in decimal representation of 1 7 \frac{1}{7}

Yatin Khanna - 4 years, 11 months ago

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