Which Number Falls In the Category?

2017 2018 2025 1733 2073

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1 solution

Naren Bhandari
Feb 24, 2018

1 2 3 4 5 6 7 8 9 10 \begin{aligned} & 1 \\& 2 \quad 3 \\& 4 \quad 5 \quad 6 \\& 7\quad 8 \quad 9 \quad 10 \\& \vdots\end{aligned} We note that the numbers in the each row is equal to rowth number and every row ends up with sum of r t h r^{th} rows.

Let the r j r_j be the any row and 2010 2010 should also fall in any of the r j r_j row number. Then we note that r = 1 j 1 r < 2010 r = 1 j r 1953 < 2010 2016 r = 1 63 1 r < 2010 r = 1 63 r \begin{aligned}&\displaystyle\sum_{r= 1}^{j-1} r < 2010 \leq \displaystyle\sum_{r=1 }^{j}r\\& 1953 < 2010 \leq 2016 \\& \displaystyle\sum_{r=1 }^{63-1} r < 2010 \leq \displaystyle\sum_{r=1}^{63} r \end{aligned} Shows that 2010 2010 falls in 6 3 r d 63^{rd} row which has 63 distinct number from 1954 to 2016 and 2010 is at 7th position before from back ( 2016 ) or 56th position after from 1954.

Now the number exactly below the 2010 is in the 64th row at the 56th position after from 2017 and 7th position back from 2080 .

Therefore the number just below 2010 will be 2080 7 = 2073 2080 -7 =\boxed{2073} .

Thank you for sharing a nice solution.

Hana Wehbi - 3 years, 3 months ago

Started out the same way, but used the fact that the number in the the row below gets x + (r-1). So in this case 2010+63(since the number below 2010 is in de 64th row)

Peter van der Linden - 3 years, 3 months ago

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